[stump_breaker]

I thought I had it figured out but I guess I do not. They way a stock 4WD setup works is torque is transferred to opposing wheels right? So when it gets in a slippery bind, driver rear and passenger front should have the most torque. Yesterday I took my old '86 into my back pond and played a little. No matter what I did, the most power was transferred to both wheels on the passenger side while the drivers side turned at about 1/4 to 1/2 the speed of the passenger side. All four wheels constantly turned but it was only the wheels on the passenger side that was getting the most power in that slippery goop.

I guess I don't understand axle slip yet. BTW, I was in 4 low and 2nd gear.

It was fun though. Wish I had thought to have my buddy take some digital clips of it.

 

[2719]

I beleive that under ideal traction all tires have equal torque applied to them. As a tire loses traction more torque is applied to the tire. So which ever tire is in the slickest snot

being left or right it will get the most torque. With the 231 case in any 4wd selection you will have one front spinning and one rear, these can be on either side. With the 242 case in 4wd fulltime a front or rear will spin. The other 4wd seetings being the same as the 231.

Please anyone correct me if i'm wrong

 

[2586]

Without a L/S or locker the wheel with the LEAST traction will get the MOST power. 2WD or 4WD, front or rear, it is the tire with the LEAST grip that spins.

 

[Guest]

before i was locked my 89 would spin only front and rear tire on passenger side. Talk about not getting anywhere.

 

[1608]

my selectrac will spin one wheel in full time 4WD, and can spin either left or right, one each front and rear in part time 4WD: left front + left rear, or left front + right rear, or right front + right rear, or right front + left rear.
It all depends on which tires have the traction - the others will spin first.

I do not have a limited slip or any locker, just the transfercase.

Steve